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28n^2=-128-144n
We move all terms to the left:
28n^2-(-128-144n)=0
We add all the numbers together, and all the variables
28n^2-(-144n-128)=0
We get rid of parentheses
28n^2+144n+128=0
a = 28; b = 144; c = +128;
Δ = b2-4ac
Δ = 1442-4·28·128
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(144)-80}{2*28}=\frac{-224}{56} =-4 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(144)+80}{2*28}=\frac{-64}{56} =-1+1/7 $
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